WOL Guide

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New Chinese Update

The chinese version has been updated again and they added a feature i don't have alot of info. about it but it is said that its a feature where you donate legends i suppose (it told me gods in translation) in exchange of rare chests and items.

I'll post any new info i get later :)

 

☼ Purple Panda ☼

Heaven Boxes

Heaven Boxes Name	Mana	Level	What it does
4 Seas Jug	60	20	Decreases the opposing army size by 5%.
Black Sand	30	10	Decreases the defence power of your enemies by 5%
Bronze Swd.	60	20	Decreases the opposing army size by 5%.
Clay Pestle	90	30	Decreases the defensive power of your enemies by 10%
Clay Pot	30	10	Increases the attack power of your troops by 5%
Duality Blade	30	10	Increases the attack power of your troops by 5%
Fire Column	30	10	Increases the attack power of your troops by 5%
Fire Javelin	30	10	Decreases the attack power of your enemies by 5%
Fire & Ice	120	20	Increases your army size by 5%
Gold Cudgel	30	10	Decreases the attack power of your enemies by 5%
Gold Gourd	120	20	Increases your army size by 5%
Gold Lotus	90	30	Decreases the defensive power of your enemies by 10%
Han Sabre	120	20	Increases your army size by 5%
Iron Sword	30	10	Increases the defensive power of your troops by 5%
Jade Gavel	90	30	Increases the defensive power of your troops by 10%
Jade Rune	30	10	Increases the defensive power of your troops by 5%
Lapis Rune	30	10	Decreases the defence power of your enemies by 5%
Magic Sand	60	20	Decreases the opposing army size by 5%.
Parasol	30	10	Increases the defensive power of your troops by 5%
Peacemaker	120	40	Decreases the opposing army size by 10%.
Plague Rune	60	20	Decreases the opposing army size by 5%.
Quartz Rune	90	30	Increases the defensive power of your troops by 10%
Reaver Blade	60	20	Decreases the opposing army size by 5%.
Red Damask	120	40	Decreases the opposing army size by 10%.
Siege Tower	60	20	Decreases the opposing army size by 5%.
Silver Maul	90	30	Increases the attack power of your troops by 10%
Sky Spear	120	40	Decreases the opposing army size by 10%.
Speculum	90	30	Increases the attack power of your troops by 10%
Tao Glass	30	10	Decreases the attack power of your enemies by 5%
Tiger Lance	30	10	Decreases the defense power of your enemies by 5%
Vigil Bow	90	30	Increases the defensive power of your troops by 10%
War Emblem	90	30	Increases the attack power of your troops by 10%

This database was done possible thanks to JAGEX's 1 WOLcash heaven boxes :) and my fellow friends !

Some artifacts might be missing so contact me at purplepandamail@gmail.com if you see a missing one !

☼ Purple Panda ☼

Mounts

Picture	Name	Description
	Gen. Tiger	One of the Chinese ancient god beasts.@Level req.: 1@March speed +50%, Crg +20, soldier Att +10%.
	Swan	Bixiao's mount, which is breeded in white clouds. March speed +30%, Mag +2. @Level Requirement: 40

[Divination Trigram] by Nobodynat

-Theory 1 - The Easy Theory-

This is what non-mathematicians think... So sorry to call you stupid or anything

The three lines have to be the same for any prize to come in the circle. If we look at it, there is only two possible lines. - and _.

Thus we can see that there is a 2/8 chance of the lines being equal in one circle considering it has a 1/2 possibility of each line.

Put that aside, there is 1/8 chance of getting three - in a circle. Since there is 4 circles, there must be 4 times as many chances, so its 4/8 = 1/2 chance! (WRONG)

hmm but even still, it doesnt seem that likely to get so many prizes! Either Jagex got it wrong (yeah go blame them) or I must be wrong! (yes you are lol)

-Theory 3 - The Auto Lose Theory, Theory 3 extended- In this theory, I will consider this; If - is chosen to be the prize, and there is a match of three _ in a circle, you will automatically lose (everything will turn to no match OR you get another try) In this case you get a slight decrease in possibilities if the matching in one circle clashes with the chosen line. 0 circles = 4C0*(7/8)^4 = 58.6% 1 circles = 4C1*(1/8)*(6/8)^3 = 21.1% 2 circles = 4C2*((1/8)^2)*(6/8)^2 = 5.3% 3 circles = 4C3*((1/8)^3)*(6/8) = 0.6% 4 circles = 4C4*(1/8)^4 = 0.02% Auto Lose = *4C1*(1/8)*3C1*(1/8)*(6/8)^2 + 4C1*(1/8)*3C2*((1/8)^2)*(6/8) + 4C1*(1/8)*3C3*(1/8)^3] + [4C2*((1/8)^2)*2C1*(1/8)*(6/8) + 4C2*((1/8)^2)*2C2*(1/8)^2] + [4C3*((1/8)^3)*[1/8)] = 13.8% Again, there are some errors, but not the chance of success is now lower! now its at 27%!

-Theory 4 - The Rearrangement Theory (disproved) - This I once believed, due to the low sucess rate. This is now disproved, as I have seen data that does not match this. The theory goes; Let all the lines - and _ have 1/2 chance of either - or _ showing. Rearrange all lines such that there will be a maximum amount of circles that do not match. Example; --- -_- --_ _-- The example wins, but you will notice there are three _ which is in three different circles, this makes sure there are three circles with no match. In such a case, this theory gives the player the worst possible outcome. However, instead of calculating the probablility, I have seen data which counters this. I.e. a win without the worst case scenario.

-Theory 5 - The 1st Line Theory - This theory is based on the first line that was chosen. As such, the line - or _ is given. There is a 1/4 chance that the first circle matches. Then for the next 3 circles there is a probablility for having more matches, no matches and auto lose. 1 circle = 1/4*3C0*(6/8)^3 = 10.5% 2 circle = 1/4*3C1*(1/8)*(6/8)^2 = 5.3% 3 circle = 1/4*3C2*((1/8)^2)*(6/8) = 0.9% 4 circle = 1/4*3C3*(1/8)^3 = 0.05% Win % = 16.7%

-Theory 6 - The fixed line Theory- This Theory is based on the fact that the autolose theory is hard to program. That is, there is no autolose system. Instead, as the lines are chosen (1/2 to be -, 1/2 to be _), all other circles have one of these lines in them as to prevent the three of the opposite lines from appearing (lines are randomly placed obviously) As such, this makes gives the sucess chance its highest probability, as it has 1/4 chance of the last two lines to match up) 0 circles = 4C0*(3/4)^4 = 31.6% 1 circles = 4C1*((3/4)^3)*(1/4)^1 = 42.2% 2 circles = 4C2*((3/4)^2)*(1/4)^2 = 21.1% 3 circles = 4C3*((3/4)^1)*(1/4)^3 = 4.7% 4 circles = 4C4*(1/4)^4 = 0.4% As you can see, you have a 68.4% chance of winning! This is the theory with highest success, of course this doesnt seem to be the case right?

You are welcome to post your own theories, if they look sound I will post it here!      All credits to: Nobodynat / Cookie giver of [Legacy] Royal Garden  ☼ Purple Panda ☼

Chinese Market

In the Chinese version the market has much more uses than in the English version :

• Buying / Selling Legends !
• Buying / Selling Items !
• Buying / Selling Artifacts !

 






☼ Purple Panda ☼ 

One Archer Strategy

A strategy used alot by experienced especially in big fights is the single archer technique.

What u need:

1. 10 Archers per legend
2. Legends
3. Army decreasing artifacts

• With 5 legends, each with 1 archer (i prefer 10), and all with 5% reducing items, you can destroy 23% /40% if you fight non-archers troops, assuming they use the same legend for all 5.

• If you have 10% items, you can destroy 41% /65% if you fight non-archers troops assuming all 5 legends are the same.

This technique can be used in both PvE and PvP battles.
Check the pic below:

Single archer technique used in SH.

☼ Purple Panda ☼